Isolating The Literal Number in an Equation, using Addition & Subtraction #5

Math for Electronics Methods for Solving Equations
11 minutes
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Transcript

All right on this slide here, we're talking about transposing terms for literal numbers. And the reason I, I put this in as you, you may just get a, especially in the in the engineering and technical fields, you just may get a, a equation with letters and you're asked to solve one of them. So I just gave you an example here. And we just picked out these letters A plus B equals c minus a, and we for whatever reason, we want to solve for a. So basically, we do this here we add an A plus on both sides. And then we add a b minus on both sides and appear and we get to a equal C minus b.

All right, and we want to find a, so I want to get a alone, sorry, divided by two. And so what I do on one side of the equation I do on the other, so the the twos cancel out here or divide out, and I'm left with the APR c minus B over two. And again, I just show you this in case you have some equations where you've got to find the, the answer or one of the literal numbers, I should say. All right, so what do you think we're going to do here? I'm going to have you do these examples. And I want you to take a few minutes and do them and then I'm gonna, I'm gonna white out the slide here and do them.

I'm going to do all of them for you. So take a few minutes, stop it, and then I will do. I think there's six here. I will do all six of them for you. Okay? All right, stop it now do it and then we'll get started when you will resume.

Okay, and the first one here, we want to find a, my equation is C equals a plus b, I want to get a loan, so all I do is subtract the B from both sides. And there you go. So my answer is C minus b equal a. Okay, in this equation here, I have our T equals r one plus r two, we want to find r one. So all I need to do is subtract and r two from each side. So I'm going to say RT minus r two equals r one, because if I subtract an RT on this side, I've got a, I mean an r two from this side, I've got to subtract an r two from this side, these go away.

And so I'm just left with R t minus r two equals r one. Again, what I do on one side of the equation I need to do on the other. Okay, on this one here, we've got V equals v one plus v two. We want to find v one. Basically, it's the same thing we've done on the previous one, and I believe the very first one. So if I want to get v one alone, what do I do?

Well, in this case, I subtractive A minus v two on both sides. And what I'm left with is vt minus v two equals v one is my answer, or there's my answer right there. So that said, I mean, basically, we've done the last three. What's changed, though? The variation, the live though the letter that represents the literal number. It really doesn't make a big deal.

Whatever it is, you treat it the same. All right. All right, let's go on. All right, on this one here, we have r squared equals z squared minus x squared, and we want to find z squared right here. So basically, what do I do subtract an x squared on both sides of the equation, like I'm showing you here, and I'm left with R squared minus x squared equal z squared whoops. All right.

All right. So that's r squared minus x squared equals z squared. Okay, we're done. Okay, on this one here, we have z squared equals r squared plus x squared. And we want to find z. So basically, we want to get z alone.

So what I do on one side of the equation I do to the other, how do I find z? if z is squared, okay. Square root of z squared is z. And on this side, I can't simplify it any more. So I've got z equals r squared plus x squared. Okay?

I really can't do anything more with these. All right? I just can't, I've got to add them. And then square square them and then add them and then find the square root. So I met the simplest form with these guys over here. Okay, let's go on.

Alright, this is the last one here, and I've got c t equal c one plus c two, and we're looking to find to solve for C two. Again, what do I do what I do to one side of the equation I do the other allow, let's just subtract a minus c one over here. Alright, and so what am I left with C t minus c one equals c two, because these go away because I'm subtracting. They just kind of subtract out. And I'm left with that. c t minus c one equals c two.

So if you look at it, yeah, the letters are different, but it's it's basically the same thing. All right. Okay, we're gonna stop here. Gonna go to the next slide. I think you've got it again. If you have some questions, you know how to contact me.

Okay, all I all I'm doing here with this screen is, even though I did them, I'm giving you the answers. I did the solutions. Previously, I whited out the slides, but I just put the answers right here. All right. Okay, let's stop here and go on to the next one. Okay, on this slide here.

If you We get a something like this, where I have a fraction equals a fraction, what I can do is I can cross multiply here to here, and then here to here, and you can see it's ad equals cb. And then if I want to solve for the variables, or the literal numbers, it becomes very easy. So for instance, on this one here, if I'm looking for a going back here, what do I do? I just divided D here and put a D here. So the DS here cancel out. And I've got CB divided by D right there.

All right. Let me do one more for you. Ah, we're doing this one here. B, B equals and let me get my pointer ready here. Okay, b equals A do receipt right there. Well, we go back over here, I'm trying to find v alone, right?

I'm looking for b. So all I do is come up here, I divide by B. I'm left with C. What I do on one side of the equation I do to the other B, so b equals A d over C, right there. Okay? So take a look at the other ones. You should be able to get them with though with those two and where I got one more slide here to go. And we'll talk about that Okay, on this one here, it says more examples for transposing terms from literal numbers.

Um, there's, although I don't know, there's maybe about 12 of them here. And I'd like you to, even though I've given you the answers, you can see right here, and so on, try to do them. How did I get the answers, and what I'm going to do is not on this video, but on the next section, all I'm going to do is record how to find the answers to these like I did in the previous example a couple of slides up there. Now if you need that, look at it. If you don't need it, then you can just skip it, but it's there. Maybe you can do like 10 of them and there's two that you're a little fuzzy on Well, you can kind of go through the video fast forward and so forth and find the ones that you Want to look at, but they'll be on the next section.

So I'm going to end this section here. And the video on how to find the solutions on these problems will be in the next section. It'll say solutions for transposing terms for literal numbers. You'll know what that means. All right. With that said, I'm going to stop this here.

And we're going to end this section and we'll see in the last one in, in this sequence of, of transposing literal numbers.

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