BEGIN:VCALENDAR
VERSION:2.0
CALSCALE:GREGORIAN
BEGIN:VEVENT
URL:https://www.learndesk.us/class/4795746681356288/lesson/1870c8cd46d33387840f0a2dd4d4a0af?ref=outlook-calendar
SUMMARY:UNIT 11
DTSTART;TZID=America/Los_Angeles:20260501T190000
DTEND;TZID=America/Los_Angeles:20260501T200000
LOCATION:https://www.learndesk.us/class/4795746681356288/lesson/1870c8cd46d33387840f0a2dd4d4a0af?ref=outlook-calendar
DESCRIPTION: In a hydrocarbon where all the carbon atoms have single bonds and no rings are involved, the compound will have the maximum number of hydrogen atoms. In other words, the compound is said to be saturated. When there is the addition of double or triple bonds or the incorporation of rings, this prevents the compound from reaching the maximum number of hydrogen atoms, rendering the atom ‘deficient’ in hydrogens. This is further compounded by the addition of atoms other than carbon or hydrogen, which can impact the number of hydrogens a carbon atom can bear. The index of hydrogen deficiency (IHD), also known as the degree of unsaturation, refers to the number of π bonds or rings
present. For example, a double bond will have an IHD=1 as it has 1 π bond, and a triple bond will have an IHD=2 as it contains 2 pi bonds. The equation for IHD is as below:
 Note: The formula is not applicable to all molecular configurations.

https://www.learndesk.us/class/4795746681356288/lesson/1870c8cd46d33387840f0a2dd4d4a0af?ref=outlook-calendar
STATUS:CONFIRMED
SEQUENCE:3
BEGIN:VALARM
TRIGGER:-PT10M
DESCRIPTION:Class Reminder
ACTION:DISPLAY
END:VALARM
END:VEVENT
END:VCALENDAR